if sin θ+12sin2θ=m cosθ এবং sinθ-12sin 2θ=n cosθ হলে m2-n2=?

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

$i f \sin θ + \frac{1}{2} \sin 2 θ = m \cos θ$ এবং $\sin θ - \frac{1}{2} \sin 2 θ = n \cos θ$ হলে $m^{2} - n^{2}$ =?

4√mn

4mn

1/(mn)

1/√ (mn)

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