If f(x)=2x+12x-1then find the value of f(x)+1f(x)-1 will be .

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

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$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

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$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

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$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

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$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

$If f (x) = \frac{2 x + 1}{2 x - 1} then find the value of \frac{f (x) + 1}{f (x) - 1} will be .$

-2x

$x^{2}$

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