∫sin xdx4-cos2x=?

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$- 2 \cos^{- 1} (x) + c$

$- \sin^{- 1} (\frac{\cos x}{2}) + c$

$- 2 \sin^{- 1} (x) + c$

$- \frac{\sin^{- 1} (x)}{2} + c$

2019

লগইন করুন

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

∫sin xdx4-cos2x=?

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$

$\int \frac{\sin x d x}{\sqrt{4 - c o s^{2} x}} = ?$