2(sinxcosx +3) =3 cosx + 4 sinx , 0<x<π

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

$2 (\sin x \cos x + \sqrt{3}) = \sqrt{3} \cos x + 4 \sin x, 0 < x < π$

$= {\frac{π}{3}, \frac{2 π}{3}}$

2017

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