y=tan-11+x1-x হলে dydx=?

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

$y = \tan^{- 1} \frac{1 + x}{1 - x}$ হলে $\frac{d y}{d x} = ?$

$\frac{1}{1 - x^{2}}$

$\frac{1}{1 + x}$

$\frac{x}{1 + x^{2}}$

$\frac{1}{1 + x^{2}}$

লগইন করুন