f(x)= x+2x(x+3) + 3x + 1x(x + 4) হলে limx→∞ x∫x = ?

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

$f (x) = \frac{x + 2}{x (x + 3)} + \frac{3 x + 1}{x (x + 4)}$ হলে $\lim_{x \to \infty} x \int (x) = ?$

$\frac{3}{4}$

2022

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