যদি 5 tan θ = 4 হয় তাহলে 5 sinθ - 3cos θsinθ+2cosθ=? | Address Academy Question

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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5/14

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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5/14

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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5/14

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

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যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

6/16

5/14

1/8

যদি $5 \tan θ = 4$ হয় তাহলে $\frac{5 \sin θ - 3 \cos θ}{\sin θ + 2 \cos θ} = ?$

6/15

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