যদি y = cos2x হয় তবে, dydx =কত?

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

যদি y = $\sqrt{\cos 2 x}$ হয় তবে, $\frac{dy}{dx}$ =কত?

$\frac{- \sin 2 x}{\sqrt{\cos 2 x}}$

$\frac{\cos 2 x}{\sqrt{\sin 2 x}}$

$\frac{2 sinx}{\sqrt{tanx}}$

$\frac{\tan 2 x}{\sqrt{\sin 2 x}}$

2003

লগইন করুন