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A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]
A student wants to cool 250g of diet 7-up initially at 27 degree celcious by adding ice initially at -18 degree C. How much ice should he add so that the final temperature will be 0 degree C with all the ice melted?[Assume that the container is not taking any heat and specific heat of 7 up 4186 J/K.degree Celcious.specific heat of ice =2000 J/K degree Celcious and the latent heat of ice =3.34*105]